Class XII Physics | Topic: Electrostatics
CBSE Physics Problem of the Day
Class XI–XII | NCERT Based
Electrostatics
A small sphere carrying a charge of
\(2 \,\mu C\) is placed at a distance of
\(0.5\,m\) from another sphere carrying a charge of
\(8 \,\mu C\).
Calculate the electrostatic force between them. State whether the force is attractive or repulsive.
Calculate the electrostatic force between them. State whether the force is attractive or repulsive.
Detailed Solution
Using Coulomb’s Law:
\[ F = k\frac{q_1 q_2}{r^2} \]Given:
\[ q_1 = 2 \times 10^{-6} C \] \[ q_2 = 8 \times 10^{-6} C \] \[ r = 0.5\,m \] \[ k = 9 \times 10^9 \, Nm^2/C^2 \]Substituting the values:
\[ F = 9 \times 10^9 \times \frac{ (2 \times 10^{-6})(8 \times 10^{-6}) }{ (0.5)^2 } \] \[ F = 9 \times 10^9 \times \frac{ 16 \times 10^{-12} }{ 0.25 } \] \[ F = 0.576\,N \]
Answer: \(0.576\,N\) (Repulsive Force)
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